A) 1
B) -1
C) \[_{l}2\]
D) \[\frac{1}{{{n}^{2}}}\]
Correct Answer: B
Solution :
Kinetic energy\[K=\frac{Z{{e}^{2}}}{8\pi {{\varepsilon }_{0}}r}\] Total energy \[U=\frac{Z{{e}^{2}}}{8\pi {{\varepsilon }_{0}}r}\] \[K:U=1:-1=-1\]
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