A) \[2\]
B) \[3\]
C) \[4\]
D) \[6\]
Correct Answer: B
Solution :
\[[Co{{({{H}_{2}}O)}_{6}}]C{{l}_{2}}\xrightarrow{{}}{{[Co{{({{H}_{2}}O)}_{6}}]}^{+2}}+2C{{l}^{-}}\] \[\therefore \]Total number of ions produced \[=3\]
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