A) \[3\]
B) \[4\]
C) \[6\]
D) \[7\]
Correct Answer: C
Solution :
\[Cr\](atomic number \[=24\]) \[=1{{s}^{2}},2{{s}^{2}}\text{ }2{{p}^{6}},3{{s}^{2}}\text{ }3{{p}^{6}}\text{ }3{{d}^{5}},4{{s}^{1}}\] shows, oxidation state from \[+1\] to \[+6\].
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