A) \[C{{H}_{4}}\]
B) \[{{C}_{2}}{{H}_{6}}\]
C) \[{{C}_{2}}{{H}_{4}}\]
D) \[{{C}_{2}}{{H}_{2}}\]
Correct Answer: D
Solution :
\[HC\equiv CH\xrightarrow[-\frac{1}{2}{{H}_{2}}]{Hot\,Na}\underset{\begin{smallmatrix} Mono\,sodium \\ acetylide \end{smallmatrix}}{\mathop{H-C\equiv CNa}}\,\xrightarrow[(-\frac{1}{2}{{H}_{2}})]{Na}\] \[\underset{Di\,sodium\,acetylide}{\mathop{NaC\equiv CNa}}\,\]
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