A) \[{{C}_{3}}{{H}_{7}}COOH\]
B) \[{{C}_{2}}{{H}_{5}}COOH\]
C) \[{{C}_{4}}{{H}_{9}}COOH\]
D) \[HCOOH\]
Correct Answer: B
Solution :
\[C{{H}_{3}}C{{H}_{2}}MgBr+O=C=O\xrightarrow{{}}\] \[C{{H}_{3}}-C{{H}_{2}}\underset{{{H}^{+}}\downarrow {{H}_{2}}O}{\mathop{-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-}}\,OMgBr\]
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