A) zero
B) \[2\]
C) \[3\]
D) \[4\]
Correct Answer: B
Solution :
Total isomers of \[{{C}_{3}}{{H}_{10}}\] are two. Structure are, \[\underset{\text{Butane}}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{3}}}}\,\]and \[\underset{\text{2-methyl propane}}{\mathop{C{{H}_{3}}-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{CH}}\,}}\,-C{{H}_{3}}}}\,\]
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