A) 4.58 eV
B) 2.28 eV
C) 1.14 eV
D) 0.23 eV
Correct Answer: B
Solution :
Work function \[W=\frac{hc}{{{\lambda }_{0}}}=\frac{12375}{{{\lambda }_{0}}\,\text{in}\,\overset{\text{0}}{\mathop{\text{A}}}\,}eV\] \[=\frac{12375}{5420}eV=2.28\,eV\]
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