RAJASTHAN PMT Rajasthan - PMT Solved Paper-2003

  • question_answer
    The wavelength associated  with an electron accelerated through a potential difference of 100V is nearly

    A)  \[100\,\overset{\text{o}}{\mathop{\text{A}}}\,\]                          

    B)  \[123\,\overset{\text{o}}{\mathop{\text{A}}}\,\]

    C)  \[1.23\,\overset{\text{o}}{\mathop{\text{A}}}\,\]         

    D)         \[0.123\,\overset{\text{o}}{\mathop{\text{A}}}\,\]

    Correct Answer: C

    Solution :

    de-Broglie wavelength associated with  electron,                             \[\lambda =\frac{h}{m\upsilon }=\frac{h}{\sqrt{2m{{E}_{K}}}}=\frac{h}{\sqrt{2me}V}\] (for electron, \[{{E}_{K}}=eV\]) \[=\frac{12.3}{\sqrt{V}}\overset{{}^\circ }{\mathop{\text{A}}}\,=\frac{12.3}{\sqrt{100}}\overset{{}^\circ }{\mathop{\text{A}}}\,\]  \[=1.23\overset{{}^\circ }{\mathop{\text{A}}}\,\]


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