RAJASTHAN PMT Rajasthan - PMT Solved Paper-2003

  • question_answer
    Three bulbs of 40 W, 60 W and 100 W are arranged in series across a 220 V supply. The bulb giving maximum brightness is of

    A)  40 W

    B)  60 W

    C)  100 W

    D)  all give equal brightness

    Correct Answer: A

    Solution :

    When bulbs are connected in series, the current in each bulb remains same. As power \[P={{i}^{2}}R,\] so, the bulb having maximum resistance will appear brightest. The resistance of a bulb, \[R=\frac{{{V}^{2}}}{p}\propto \frac{1}{p}\] (For same V) \[\therefore \]The bulb of least power possesses maximum resistance. Hence, 40 W bulb will appear brightest when connected in series with other bulbs.


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