A) zero group
B) Ist group
C) VIIth group
D) IIIrd group
Correct Answer: A
Solution :
\[\underset{Radium}{\mathop{_{88}R{{a}^{226}}}}\,\xrightarrow{{}}\underset{Radon}{\mathop{_{86}R{{n}^{222}}}}\,{{+}_{2}}H{{e}^{4}}\] Therefore, by removing a-particle from Radium, the new element formed is Radon which belongs to zero group.
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