A) 1-Butanol
B) 2-Butene
C) 1-Butene
D) 2-Butanol
Correct Answer: C
Solution :
\[\underset{\text{1-Chlorobutane}}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}Cl}}\,\xrightarrow[(-HCl)]{Alc.\,KOH}\] \[\underset{1-Butene}{\mathop{C{{H}_{3}}C{{H}_{2}}CH=C{{H}_{2}}}}\,\]
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