RAJASTHAN PMT Rajasthan - PMT Solved Paper-2004

  • question_answer
    If in a diode valve, the plate potential becomes double, then plate current will be:

    A)  \[2\sqrt{2}\] times                        

    B)  8 times

    C)  \[3\sqrt{3}\] times        

    D)         2 times

    Correct Answer: A

    Solution :

    The Childs equation is\[{{I}_{p}}\propto {{V}_{p}}^{3/2}\] \[\therefore \]  \[I{{ & }_{p}}={{\left( \frac{V{{}_{p}}}{{{V}_{p}}} \right)}^{3/2}}{{I}_{p}}\] or            \[{{I}_{p}}={{(2)}^{3/2}}{{I}_{p}}\]                                 \[=2\sqrt{2}{{I}_{p}}\]


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