A) 5m, 10 m/s
B) 3m, 2 m/s
C) 4m, 2 m/s
D) 3m, 4 m/s
Correct Answer: A
Solution :
Displacement equation is \[x=3\,\sin \,2t+4\,\cos \,2t\] Comparing this equation with \[x={{a}_{1}}\,\sin \,\omega t\,{{a}_{2}}\,\cos \,\omega t\] We get, \[{{a}_{1}}=3,{{a}_{2}}=4,\omega =2\] \[\therefore \] \[a=\sqrt{a\,_{2}^{2}+a\,_{2}^{2}}=\sqrt{{{3}^{3}}+{{4}^{2}}}=5\,\text{metre}\] and maximum velocity \[{{\upsilon }_{\max }}=a\omega =5\times 2=10\,m/s\]
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