A) First
B) Second
C) Third
D) All same
Correct Answer: A
Solution :
Pressure \[\text{=}\frac{\text{Force}}{\text{area}}\] or \[P=\frac{F}{A}\] \[\Rightarrow \] \[P\propto \frac{1}{A}\] \[\Rightarrow \] \[\Rightarrow P\propto \frac{1}{{{r}^{2}}}\] \[(\therefore A=A\pi {{r}^{2}})\] Therefore, the sphere which has lesser area, will exert maximum pressure. Since, first sphere has small radius, so, its area will be small. Hence, it will exert maximum pressure.
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