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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2004

  • question_answer
    A train moving with 20 m/s towards a stationary observer produces frequency of 440 Hz. The apparent frequency heard will be (\[\upsilon \] = 330 m/s):

    A)  448 Hz

    B)                        455 Hz

    C)  440 Hz

    D)         468 Hz

    Correct Answer: D

    Solution :

    Apparent frequency heard by stationary observer\[n=n\left( \frac{\upsilon }{\upsilon ={{\upsilon }_{s}}} \right)\] Here: \[\upsilon \] = 330 m/sec, \[{{\upsilon }_{s}}\] = 20 m/s \[n=440\,Hz\] \[\therefore \]  \[n=440\left( \frac{330}{330-20} \right)\]                                                  \[\begin{align}   & =468.38 \\  & \approx 468Hz \\ \end{align}\]


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