A) \[\pi {{\left( \frac{2{{\mu }^{2}}}{g} \right)}^{2}}\]
B) \[2\pi {{\left( \frac{u}{g} \right)}^{2}}\]
C) \[\pi {{\left( \frac{u}{2g} \right)}^{2}}\]
D) \[\pi {{\left( \frac{{{u}^{2}}}{g} \right)}^{2}}\]
Correct Answer: D
Solution :
Range R \[=\frac{{{\upsilon }^{2}}\sin 2\theta }{g}\] Range R will be maximum if sin \[2\theta =1\] so, \[{{R}_{\max }}=\frac{{{\upsilon }^{2}}}{g}\] Maximum area covered \[=\pi {{({{R}_{\max }})}^{2}}=\pi {{\left( \frac{{{\upsilon }^{2}}}{g} \right)}^{2}}\]
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