A) \[HI\]
B) \[HCl\]
C) \[HBr\]
D) \[HF\]
Correct Answer: A
Solution :
In the reaction, \[ROR+HX\xrightarrow{{}}ROH+RX\] the correct order of reactivity of halogen acids is: \[HI>HBr>HCl\] The smaller alkyl group always forms alkyl halide while bigger alkyl group (or aryl group) forms alcohol (or phenol). \[C{{H}_{3}}OCH{{(C{{H}_{3}})}_{2}}+HI\xrightarrow{{}}C{{H}_{3}}I\] \[+{{(C{{H}_{3}})}_{2}}CHOH\] \[C{{H}_{3}}O{{C}_{6}}{{H}_{5}}+HI\xrightarrow{{}}C{{H}_{3}}I+\underset{Phenol}{\mathop{{{C}_{6}}{{H}_{5}}OH}}\,\]
You need to login to perform this action.
You will be redirected in
3 sec
