A) \[{{C}_{2}}{{H}_{4}}\]
B) \[C{{H}_{4}}\]
C) \[CO\]
D) \[GaC{{l}_{3}}\]
Correct Answer: D
Solution :
\[Ga\] in \[GaC{{l}_{3}}\] has empty orbitals due to which it act as acceptor of electron-pair (Lewis acid).
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