A) \[{{B}_{2}}{{O}_{3}}\]
B) \[Be{{O}_{2}}\]
C) \[A{{l}_{2}}{{O}_{3}}\]
D) None of these
Correct Answer: A
Solution :
Boric oxide \[({{B}_{2}}{{O}_{3}})\] is a Lewis acid. It accepts electron pair from \[O{{H}^{-}}\] of \[{{H}_{2}}O\] molecule and thus act as Lewis acid (monobasic). \[{{B}_{2}}{{O}_{3}}+3{{H}_{2}}O\xrightarrow{{}}2{{H}_{2}}B{{O}_{3}}\] \[{{H}_{3}}B{{O}_{3}}+{{H}_{2}}O\xrightarrow{{}}B(OH)_{4}^{-}+{{H}^{+}}\]
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