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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2004

  • question_answer
    The number of \[\alpha -\] and \[\beta -\]particles lost when \[_{92}{{U}^{238}}\] changes to  \[_{82}P{{b}^{206}}\] :

    A)  \[8\alpha ,\,6\beta \]                   

    B)         \[6\alpha ,\,6\beta \]

    C)  \[6\alpha ,\,6\beta \]                   

    D)         \[4\alpha ,\,4\beta \]

    Correct Answer: A

    Solution :

    The numbers of \[\alpha \]-particles \[=\frac{238-206}{4}\] \[=\frac{32}{4}=8\] The number of \[\beta \]-particles                 \[=2\times 8-(92-82)\]                 \[=16-10=6\]


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