A) angular momentum
B) linear momentum
C) force
D) energy
Correct Answer: A
Solution :
The dimension of Plancks constant is given by \[h=\frac{E}{\upsilon }=\frac{[M{{L}^{2}}{{T}^{-2}}]}{[{{T}^{-1}}]}\] \[=[M{{L}^{2}}{{T}^{-1}}]\] Dimension of angular momentum is = moment of inertia x angular velocity \[=[M{{L}^{2}}{{T}^{-1}}]=[M{{L}^{2}}{{T}^{-1}}]\] So, the dimension of Plancks constant is same as of angular momentum.
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