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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2005

  • question_answer
    The no. of turns in primary and secondary of a   transformer are 5 and 10 and mutual inductance of transformer is 25 henry. Now, the no. of turns in primary and secondary are 10 and 5, the  new mutual inductance will be:

    A)  6.25 H                                  

    B)  12.5H

    C)  25 H                     

    D)         50 H

    Correct Answer: C

    Solution :

    Mutual inductance of transformer \[M\propto {{N}_{1}}{{N}_{2}}\] \[\frac{{{M}_{1}}}{{{M}_{2}}}=\frac{{{N}_{1}}{{N}_{2}}}{N{{}_{1}}N{{}_{2}}}\] \[\frac{25}{{{M}_{2}}}=\frac{5\times 10}{10\times 5}\] \[\therefore \]  \[{{M}_{2}}=25\,henry\]


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