A) - 3.4 eV
B) - 6.6 eV
C) -8.1eV
D) -10.2eV
Correct Answer: D
Solution :
Energy of nth orbit of hydrogen atom \[{{E}_{n}}=-\frac{13.6}{{{n}^{2}}}eV\] The energy absorbed, when an electron jumps from the first energy level (n = 1) to second level (n = 2) \[=-13.6\times \left( \frac{1}{{{n}_{1}}^{2}}-\frac{1}{{{n}_{2}}^{2}} \right)\] \[=-13.6\left[ \frac{1}{{{(1)}^{2}}}-\frac{1}{{{(2)}^{2}}} \right]\] \[=-13.6\times \frac{3}{4}\] \[=-10.2\,eV\]You need to login to perform this action.
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