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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2005

  • question_answer
    A body of uniform cross-sectional area floats in a liquid of density thrice its value. The fraction of exposed height will be:

    A)  \[\frac{2}{3}\]                                  

    B)  \[\frac{5}{6}\]

    C)  \[\frac{1}{6}\]                  

    D)         \[\frac{1}{3}\]

    Correct Answer: A

    Solution :

    Here area is uniform, so portion of immersed height\[=\frac{1}{3}\] (Here : the ratio of density of body and density of water \[=\frac{1}{3})\] Therefore, fraction of exposed height will\[1-\frac{1}{3}=\frac{2}{3}\]


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