A) \[HCOOH\]
B) \[C{{H}_{3}}COOH\]
C) \[C{{H}_{3}}C{{H}_{2}}COOH\]
D) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}COOH\]
Correct Answer: A
Solution :
Formic acid reduces Tollens reagent \[\underset{Tollens\,\,reagent}{\mathop{2Ag(N{{H}_{3}})_{2}^{+}}}\,+\underset{Formic\,\,acid}{\mathop{HCOOH}}\,\xrightarrow{{}}\underset{Silver}{\mathop{2Ag}}\,+C{{O}_{2}}\] \[+2NH_{4}^{+}+2N{{H}_{3}}\] Because it behave both on an acid and as an aldehyde \[\underset{Formic\,\,acid}{\mathop{H-\overset{\begin{smallmatrix} O \\ |\,\,| \end{smallmatrix}}{\mathop{C}}\,-OH}}\,\]\[\underset{Carboxylic\,\,acid}{\mathop{H-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-OH}}\,\]\[\underset{Aldehyde}{\mathop{H-\overset{\begin{smallmatrix} O \\ |\,\,| \end{smallmatrix}}{\mathop{C}}\,-OH}}\,\]
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