A) \[He\]
B) \[B\]
C) \[Li\]
D) \[Na\]
Correct Answer: A
Solution :
The electron affinity of \[Be\] is similar to that of helium\[(He)\]. Because the electronic configuration of \[Be\] is similar to\[He\]. \[_{4}Be=1{{s}^{2}},\,\,2{{s}^{2}}\] \[_{2}He:1{{s}^{2}}\]
You need to login to perform this action.
You will be redirected in
3 sec
