A) \[3.47\,\,atm\]
B) \[5.07\,\,atm\]
C) \[2.09\,\,atm\]
D) \[4.03\,\,atm\]
Correct Answer: B
Solution :
We know that Osmotic pressure\[(\pi )=\frac{n}{V}RT\] \[n=\frac{weight\,\,of\,\,solute\,\,(w)}{molar\,\,mass\,\,of\,\,solute\,\,(M)}\] \[T=273+150=423\] \[\therefore \] \[\pi =\frac{wRT}{MV}\] \[=\frac{5\times 0.0821\times 1000\times 423}{342\times 1000}=5.07\] [mol. mass of\[{{C}_{12}}{{H}_{22}}{{O}_{11}}\] \[=(12\times 12)+22+(11\times 16)\] \[=144+22+176=342]\]
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