A) \[\left( \frac{\pi }{6} \right)rad\,{{s}^{-1}}\]
B) \[\left( \frac{\pi }{60} \right)rad\,{{s}^{-1}}\]
C) \[\left( \frac{\pi }{30} \right)rad\,{{s}^{-1}}\]
D) \[\left( \frac{\pi }{15} \right)rad\,{{s}^{-1}}\]
Correct Answer: C
Solution :
Angular velocity\[=\frac{\Delta \theta }{\Delta t}=\frac{2\pi }{60}rad\,\,{{s}^{-1}}\] \[=\frac{\pi }{30}rad\,\,{{s}^{-1}}\] Reason: A second hand makes an angle of \[2\pi \] (i.e.,\[{{360}^{o}}\]) is one minute, (i.e.,\[60\,\,s\]).
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