A) \[30{}^\circ \]
B) \[{{60}^{\text{o}}}\]
C) \[{{120}^{\text{o}}}\]
D) \[{{45}^{\text{o}}}\]
Correct Answer: B
Solution :
For prism \[\mu =\frac{\sin \left( \frac{A+{{\delta }_{m}}}{2} \right)}{\sin \left( \frac{A}{2} \right)}A\to \]angle of prism Here,\[A={{60}^{o}}\] \[\Rightarrow \] \[\sqrt{3}\times \sin {{30}^{o}}=\sin \left( \frac{{{60}^{o}}+{{\delta }_{m}}}{2} \right)\] \[\Rightarrow \] \[\sin \left( \frac{{{60}^{o}}+{{\delta }_{m}}}{2} \right)=\sin {{60}^{o}}\] \[\Rightarrow \] \[{{60}^{o}}+{{\delta }_{m}}={{120}^{o}}\Rightarrow {{\delta }_{m}}={{60}^{o}}\]
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