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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2006

  • question_answer
    . Separation between slits is halved and between secreen and slits is doubled. Final fringe width if original is w:

    A)  w                                          

    B)         9w

    C)         4w                                        

    D)         2w

    Correct Answer: C

    Solution :

    In interference fringe with\[=\frac{\lambda \,\,D}{d}=w\](given)                 \[w=\frac{\lambda \times 2\,\,D}{\frac{d}{2}}=4\times \frac{\lambda \,\,D}{d}=4w\]


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