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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2006

  • question_answer
    If velocity of a charged particle is doubled and strength of magnetic field is halved, then radius becomes :

    A)  8 times                               

    B)         2 times

    C)         4 times                               

    D)         3 times

    Correct Answer: C

    Solution :

    Force\[=qvB=\frac{m{{v}^{2}}}{r}=\](centripetal force) \[\Rightarrow \]               \[r=\frac{mv}{qB}\] \[\therefore \]  \[r=\frac{m\times 2\,\,v}{q\times \frac{B}{2}}=4\,\,r\]


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