RAJASTHAN PMT Rajasthan - PMT Solved Paper-2006

  • question_answer
    A closed organ pipe and an open organ pipe are tuned to the same fundamental frequency. What is the ratio of their lengths?

    A)  1 : 2                                      

    B)         2 : 1                      

    C)         2 : 3                                      

    D)         4 : 3

    Correct Answer: A

    Solution :

    Avoiding end correction, the length of closed organ pipe is                 \[{{l}_{1}}=\frac{{{\lambda }_{1}}}{4}\]     or     \[{{\lambda }_{1}}=4{{l}_{1}}\] The length of open organ pipe is                 \[{{l}_{2}}=\frac{{{\lambda }_{2}}}{2}\]     or     \[{{\lambda }_{2}}=2{{l}_{2}}\] Here,     \[{{n}_{1}}={{n}_{2}}\] \[\Rightarrow \]               \[\frac{v}{{{\lambda }_{1}}}=\frac{v}{{{\lambda }_{2}}}\] or            \[\frac{v}{4{{l}_{1}}}=\frac{v}{4{{l}_{2}}}\] Therefore,\[{{l}_{1}}:{{l}_{2}}=1:2\]


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