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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2006

  • question_answer
    A capacitor of capacitance \[6\mu F\] is charged upto 100 V. The energy stored in the capacitor is:

    A)  0.6 J                                     

    B)         0.06 J                   

    C)         0.03 J                   

    D)         0.3 J

    Correct Answer: C

    Solution :

    The energy stored in the capacitor is given by                 \[U=\frac{1}{2}C{{V}^{2}}\] Given:   \[C=6\times {{10}^{-6}}F,\,\,V=100\,\,V\] So,          \[U=\frac{1}{2}\times 6\times {{10}^{-6}}\times {{(100)}^{2}}\]                 \[=3\times {{10}^{-2}}J\]                 \[=0.03\,\,J\]


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