A) \[HCHO\]
B) \[C{{H}_{3}}CHO\]
C) \[C{{H}_{3}}COC{{H}_{3}}\]
D) \[{{C}_{2}}{{H}_{5}}OH\]
Correct Answer: A
Solution :
lodoform test is given by those compounds which have\[-\overset{\begin{smallmatrix} O \\ |\,\,| \end{smallmatrix}}{\mathop{C}}\,-C{{H}_{3}}\] group or on oxidation yields this group. Formaldehyde does not have\[-\overset{\begin{smallmatrix} O \\ |\,\,| \end{smallmatrix}}{\mathop{C}}\,-C{{H}_{3}}\]group, hence it does not give iodoform test.
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