A) oxidizing property
B) acidic property
C) basic property
D) reducing property
Correct Answer: D
Solution :
\[S{{O}_{2}}\] act as bleaching agent due to its reducing property. \[S{{O}_{2}}+2{{H}_{2}}O\xrightarrow{{}}{{H}_{2}}S{{O}_{4}}+2H\] coloured matter\[+\,\,\,\,\,[H]\to \]colorless matter.
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