RAJASTHAN PMT Rajasthan - PMT Solved Paper-2007

  • question_answer
    A current of 2 A flowing through a conductor produces 80 Jot heat in 10s. The resistances of the conductor is

    A)  \[0.5\,\Omega \]                            

    B)  \[2\,\Omega \]

    C)  \[4\,\Omega \]               

    D)         \[20\,\Omega \]

    Correct Answer: B

    Solution :

    From Joules law,                 \[H={{i}^{2}}Rt\] Given,\[H=80\,\,J,\,\,i=2A,\,\,t=10\,\,s\] \[\therefore \]  \[80={{(2)}^{2}}\times R\times 10\] \[\Rightarrow \]               \[R=\frac{80}{4\times 10}=2\Omega \]


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