A) \[I\] is halved
B) B is halved
C) r is doubled
D) both B and \[I\] are doubled
Correct Answer: D
Solution :
When a circular flexible loop is placed in a magnetic field, a deflecting torque \[\left( \tau \right)\] acts on it, this is given by \[\tau =MB\,\,\sin \,\,\theta \] Also, \[M=I\,\,A\] \[\therefore \] \[\tau =I\,\,A\,\,B\,\,\sin \theta =I\pi {{r}^{2}}B\,\,\sin \,\,\theta \] When \[B\] and \[I\] are doubled, the torque is doubled, hence tension is doubled.
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