A) \[C{{H}_{3}}\underline{C}OOH\]
B) \[C{{H}_{3}}\underline{C}ON{{H}_{2}}\]
C) \[C{{H}_{3}}\underline{C}{{H}_{2}}OH\]
D) \[C{{H}_{3}}\underline{C}H=C{{H}_{2}}\]
Correct Answer: C
Solution :
\[\underset{s{{p}^{2}}}{\mathop{C{{H}_{3}}-\overset{\begin{smallmatrix} O \\ |\,| \end{smallmatrix}}{\mathop{C}}\,-OH}}\,\] \[\underset{s{{p}^{2}}}{\mathop{C{{H}_{3}}-\overset{\begin{smallmatrix} O \\ |\,| \end{smallmatrix}}{\mathop{C}}\,-N{{H}_{2}}}}\,\] \[C{{H}_{3}}-\underset{\begin{smallmatrix} |\,\,\,\,\,s{{p}^{3}} \\ H \end{smallmatrix}}{\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{C}}}\,-OH\] \[\underset{s{{p}^{2}}}{\mathop{C{{H}_{3}}-\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{C}}\,=C{{H}_{2}}}}\,\]
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