A) Methyl iodide
B) Ethyl iodide
C) Ethyl bromide
D) Propyl bromide
Correct Answer: D
Solution :
In the formation of an alkane from Grignard reagent, alkyl group always comes from Grignard reagent. Hence, the number of carbon atoms in the Grignard reagent and alkane formed from Grignard reagent will be identical. So, the original alkyl halide is propyl bromide.
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