A) zero
B) one
C) two
D) four
Correct Answer: C
Solution :
\[{{O}_{2}}=8+8=16\]. \[=\sigma 1{{s}^{2}},\,\,\sigma 1{{s}^{2}},\,\,\sigma 2{{s}^{2}},\,\,\overset{*}{\mathop{\sigma }}\,2{{s}^{2}},\,\,\sigma 2p_{z}^{2},\] \[\pi 2p_{y}^{2},\,\,\pi 2p_{x}^{2},\,\,\overset{*}{\mathop{\pi }}\,2p_{y}^{1}\overset{*}{\mathop{\pi }}\,2p_{x}^{1}\] \[\therefore \]Number of unpaired electrons\[=2\]
You need to login to perform this action.
You will be redirected in
3 sec
