RAJASTHAN PMT Rajasthan - PMT Solved Paper-2008

  • question_answer
    Under the influence of a uniform magnetic field a charged particle is moving in a circle of radius R with constant speed v. The time period of the motion

    A)  depends on v and not on R

    B)  depends on both R and v

    C)  is independent of both R and v

    D)  depends on R and not on v

    Correct Answer: C

    Solution :

    Key Idea: To move on circular path in a magnetic field, a centripetal force is provided by the magnetic force. When magnetic field is perpendicular to motion of charged particle, then                 Centripetal force = magnetic force \[ie,\]    \[\frac{m{{v}^{2}}}{R}=Bqv\] or            \[R=\frac{mv}{Bq}\] Further, time period of the motion                 \[T=\frac{2\pi R}{v}=\frac{2\pi \left( \frac{mv}{Bq} \right)}{v}\] or            \[T=\frac{2\pi m}{Bq}\] It is independent of both \[R\] and\[v\].


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