RAJASTHAN PMT Rajasthan - PMT Solved Paper-2008

  • question_answer
    The frequency of a light wave in a material is \[2\times {{10}^{14}}Hz\] and wavelength is \[5000\overset{\text{o}}{\mathop{\text{A}}}\,\]. The refractive index of material will be

    A)  1.40                                      

    B)  1.50

    C)  3.00                      

    D)         1.33

    Correct Answer: C

    Solution :

    Velocity of light waves in material is                 \[v=v\lambda \]                                                               ... (i) Refractive index of material is                 \[\mu =\frac{c}{v}\]                                                        ? (ii) where \[c\] is speed of light in vacuum or air. or            \[\mu =\frac{c}{v\lambda }\]                                                      ... (iii) Given,   \[v=2\times {{10}^{14}}Hz\]                 \[\lambda =5000\,\,\overset{\text{o}}{\mathop{\text{A}}}\,=5000\times {{10}^{-10}}m\],                 \[c=3\times {{10}^{8}}m/s\] Hence, from Eq. (iii), we get                 \[\mu =\frac{3\times {{10}^{8}}}{2\times {{10}^{14}}\times 5000\times {{10}^{-10}}}=3.00\]


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