A) less than\[\mathbf{\vec{v}}\]
B) greater than\[\mathbf{\vec{v}}\]
C) \[v\] in the direction of largest force BC
D) \[\mathbf{\vec{v}}\]remaining unchanged
Correct Answer: D
Solution :
Resultant force is zero, as three forces acting on the particle can be represented in magnitude and direction by three sides of a triangle in order. Hence, by Newtons 2nd law\[\left( \overset{\to }{\mathop{\mathbf{F}}}\,=m\frac{d\overset{\to }{\mathop{\mathbf{v}}}\,}{dt} \right)\], particle velocity \[(\overset{\to }{\mathop{\mathbf{v}}}\,)\] will be same,
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