A) \[({{\phi }_{2}}-{{\phi }_{1}}){{\varepsilon }_{0}}\]
B) \[({{\phi }_{1}}+{{\phi }_{2}})/{{\varepsilon }_{0}}\]
C) \[({{\phi }_{2}}-{{\phi }_{1}})/{{\varepsilon }_{0}}\]
D) \[({{\phi }_{1}}+{{\phi }_{2}}){{\varepsilon }_{0}}\]
Correct Answer: A
Solution :
[From Gauss law,\[\frac{\text{Charge}\,\,\text{enclosed}}{{{}_{\text{0}}}}\] = Flux leaving the surface] \[\frac{q}{{{\varepsilon }_{0}}}={{\phi }_{2}}-{{\phi }_{1}}\] \[\Rightarrow \] \[q=({{\phi }_{2}}-{{\phi }_{1}}){{\varepsilon }_{0}}\]
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