A) lone pair-lone pair repulsion
B) lone pair-bond pair repulsion
C) bond pair-bond pair repulsion
D) high electronegativity of oxygen
Correct Answer: A
Solution :
The hybridisation of oxygen in water molecule is\[s{{p}^{3}}\]. So, water molecule must be tetrahedral and have bond angle\[{{109}^{o}}28\]. But due to the presence of two lone pair of electrons on oxygen atom (repulsion between lone pair-lone pair) the bond angle decreases about \[{{104.5}^{o}}\] and the geometry becomes distorted tertrahedral or \[V-\]shaped.
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