A) \[IIA\]group and 5th period
B) \[II\,\,A\] group and 2nd period
C) \[V\,\,A\]group and 2nd period
D) \[III\,\,A\] group and 5th period
Correct Answer: A
Solution :
The electronic configuration of atomic number 38 is \[X(38):\]\[1{{s}^{2}},\,\,2{{s}^{2}}2{{p}^{6}},\,\,3{{s}^{2}}3{{p}^{6}},\,\,4{{s}^{2}}3{{d}^{10}}4{{p}^{6}},\,\,5{{s}^{2}}\] or\[1{{s}^{2}},\,\,2{{s}^{2}},2{{p}^{6}},\,\,3{{s}^{2}},\,\,3{{p}^{6}},\,\,3{{d}^{10}},\,\,4{{s}^{2}}4{{p}^{6}},\,\,5{{s}^{2}}\] Hence, it is belongs to \[II\,\,A\] group and 5th period. It is strontium\[(Sr)\].
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