A) \[\frac{molecular\,\,weight}{3}\]
B) \[\frac{molecular\,\,weight}{6}\]
C) \[\frac{molecular\,\,weight}{1}\]
D) \[\frac{molecular\,\,weight}{2}\]
Correct Answer: B
Solution :
\[\overset{+6}{\mathop{{{K}_{2}}C{{r}_{2}}{{O}_{7}}}}\,+4{{H}_{2}}S{{O}_{4}}\xrightarrow{{}}{{K}_{2}}S{{O}_{4}}+\overset{+3}{\mathop{C{{r}_{2}}}}\,{{(S{{O}_{4}})}_{3}}\] \[+4{{H}_{2}}+3[O]\] Equivalent weight \[=\frac{Molecular\,\,weight}{\begin{align} & Change\,\,in\,\,oxidation\,\,number\,\,of\,\,atoms \\ & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,present\,\,in\,\,one\,\,molecular \\ \end{align}}\] \[\therefore \]Equivalent weight\[=\frac{Molecular\,\,weight}{2\times 3}\] \[=\frac{Molecular\,\,weight}{6}\]
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