RAJASTHAN PMT Rajasthan - PMT Solved Paper-2008

  • question_answer
    The pair of species having identical shapes for molecules of both species is

    A) \[C{{F}_{4}},\,\,S{{F}_{4}}\]                        

    B)        \[Xe{{F}_{2}},\,\,C{{O}_{2}}\]

    C)        \[B{{F}_{3}},\,\,PC{{l}_{3}}\]                      

    D)        \[P{{F}_{5}},\,\,I{{F}_{5}}\]

    Correct Answer: B

    Solution :

    In\[C{{O}_{2}}\], \[C-\]atom is \[sp-\]hybridized, thus it has linear structure. In \[Xe{{F}_{2}},\,\,Xe\] is\[s{{p}^{3}}d\]hybridized with three lone-pairs of electrons on equatorial position. This minimises repulsion, hence it has also linear structure.


You need to login to perform this action.
You will be redirected in 3 sec spinner