A) \[4.0\,\,g\]
B) \[8.0\,\,g\]
C) \[12.0\,\,g\]
D) \[16.0\,\,g\]
Correct Answer: A
Solution :
\[C={{C}_{0}}{{\left( \frac{1}{2} \right)}^{y}}\] \[y=\frac{total\,\,time}{{{T}_{1/2}}}=\frac{18}{3}=6\] \[{{C}_{0}}=256\,\,g\] \[\therefore \] \[{{C}_{(undecayed)}}=256{{\left( \frac{1}{2} \right)}^{6}}=\frac{256}{64}=\mathbf{4}\,\,\mathbf{g}\]
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