A) \[\text{2}\pi \]
B) \[\text{3}\pi \]
C) \[4\pi \]
D) \[\text{5}\pi \]
Correct Answer: A
Solution :
Slope of acceleration-displacement graph\[=-{{\omega }^{2}}\] \[\therefore \] \[{{\omega }^{2}}=\tan {{45}^{o}}=1\] \[\therefore \] \[\omega =1\] But \[\omega =\frac{2\pi }{T}=1\] \[\therefore \] \[T=2\pi \]
You need to login to perform this action.
You will be redirected in
3 sec
